3[2-5(x+1)]=4(2x+1)

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Solution for 3[2-5(x+1)]=4(2x+1) equation:


Simplifying
3[2 + -5(x + 1)] = 4(2x + 1)

Reorder the terms:
3[2 + -5(1 + x)] = 4(2x + 1)
3[2 + (1 * -5 + x * -5)] = 4(2x + 1)
3[2 + (-5 + -5x)] = 4(2x + 1)

Combine like terms: 2 + -5 = -3
3[-3 + -5x] = 4(2x + 1)
[-3 * 3 + -5x * 3] = 4(2x + 1)
[-9 + -15x] = 4(2x + 1)

Reorder the terms:
-9 + -15x = 4(1 + 2x)
-9 + -15x = (1 * 4 + 2x * 4)
-9 + -15x = (4 + 8x)

Solving
-9 + -15x = 4 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
-9 + -15x + -8x = 4 + 8x + -8x

Combine like terms: -15x + -8x = -23x
-9 + -23x = 4 + 8x + -8x

Combine like terms: 8x + -8x = 0
-9 + -23x = 4 + 0
-9 + -23x = 4

Add '9' to each side of the equation.
-9 + 9 + -23x = 4 + 9

Combine like terms: -9 + 9 = 0
0 + -23x = 4 + 9
-23x = 4 + 9

Combine like terms: 4 + 9 = 13
-23x = 13

Divide each side by '-23'.
x = -0.5652173913

Simplifying
x = -0.5652173913

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